***Chemistry concentration question***?

1

Posted on : 13-02-2014 | By : My Study Coach | In : Improve Your Concentration
1 Star2 Stars3 Stars4 Stars5 Stars (No Ratings Yet)
Loading ... Loading ...

In a titration a student pipettes 10.00 mL of ammonia solution into his flask. It takes 19.47 mL of 0.278 M sulphuric acid to reach the equivalence point. Calculate the concentration of the ammonia solution in mol/L

Related posts:

  1. What was the molar concentration of the original phosphoric acid solution?
  2. Concentration of acetic acid in vinegar?
  3. What is the concentration of an acid solution ?
  4. finding the concentration?!?
  5. How do you find concentration of a weak base in titration if not given volume?

Share this :

  • Stumble upon
  • twitter

Comments (1)

is 0.278 the mole or the concentration?
If concentration then,
n=CV
0.01947×0.278
=0.0541mol-1
You will require a balanced equation to work out the conc of NH3

2NH3 + H2SO4 –> (NH4)2SO4

Therefore ratio is 1:2
n(NH3) = 2 x 0.0541
n=0.1082mol-1
therefore concentration of NH3
C=n/v
=0.1082/0.01
C=10.82mol/L-1

I chose this way, as a titration is using a standard solution (known concentration) and an unknown solution(unknown concentration).

Post a comment

Powered by Yahoo! Answers

Powered by WP Robot

Close
Remind Me Later

Sign Up for Your FREE Study Skills Video Course here