How do I solve for the molar concentration?

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Posted on : 27-12-2013 | By : My Study Coach | In : Improve Your Concentration
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What is the molar concentration of a Ca(OH)2 solution if 71.5g of Ca(OH)2 were completely dissolved in an adequate volume of solvent and brought to a final solution volume of 1550mL?

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Comments (1)

Molar concentration (or molarity, or simply M) is defined as moles of solute divided by liters of solution. Your first step is to determine how many moles of Ca(OH)2 is present in 71.5g.

Find the molecular weight of Ca(OH)2.
Ca = 40
(OH)2 = 34
There are approximately 74g of Ca(OH)2 in one mole.

You have 71.5g, so divide 71.5 by 74. You have approximately .97 moles of Ca(OH)2.

1550mL = 1.55L

Now just plug the numbers on.

Molarity = (moles of solute)/(liters of solution)
Molary = .97/1.55 = 0.63

So the molar concentration is approximately 0.63.

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