How do you work out the concentration of conjugate base and acid using henderson-hasselbach equation…?

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Posted on : 04-01-2014 | By : My Study Coach | In : Improve Your Concentration
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So the ratio of [conjugate base]/[acid] = 1.58 (using henderson-hasselbach)
And the concentration at the start is 0.05 M

The answer says [acid] = 19.37 mM
and [conjugate base] = 30.63 mM

but im not sure how to use ratios and stuff to get to that?

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Comments (1)

Two things that you have to work with:
The total concentration is 0.05M
The ratio con base: acid is 1.58:1

Te method that I use ( probably the mathematicians will have a better one) is to say that I have 1.58 molar parts of salt and 1.0 molar parts of acid . So I have 2.58 molar parts of combined salt plus acid:

molarity of salt = 1.58/2.58*0.05 = 0.03062 M = 30.62mM
molarity of acid = 1/2.56*0.05 = 0.01938 M = 19.38mM
That is how I do and as you see , it works.

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